Chemistry mole question?

I know there are a lot of questions but i just want to make sure that i got the right answers!!

Mass of crucible with copper: 21.6584 grams

Mass of copper: .6077 grams

Mass of crucible and product after heating:21.8156 grams

1) calculate the percentage of sulfur and copper in final compound?

2.) calculate the number of moles in original sample of copper?

3)how many grams of sulfur have combined with the original sample of copper?

4) how many moles of sulfur have combined with the original sample of copper?

5) what is the ratio of copper to sulfur (mole cu/mole s) to nearest whole?

6) formula of copper and sulfur?

7)what would happen to the cu/s mole ratio if some of the copper was unreacted?

8) what will happen to the cu/s male ratio if unreacted sulfur remains in the crucible?

9) what is the number of atoms of copper in the mole of copper?

10) how many atoms of copper are in your product?

11) how many atoms of sulfur are in the product?

When you are heating the copper, sulfur is being absorbed into it. To find the amount of sulfur, find the difference between the initial and final amounts: 21.8156 g - 21.6584 g = 0.1572 g sulfur. You know there are 0.6077 g copper and (0.1572 + 0.6077) = 0.7649 g total. The molecular weight of copper is 63.546 g/mol, and sulfur is 32.066 g/mol. Avagadro's number if 6.02E23 molecules/mol