How many grams of SF6 should be added to a sample of 486 g SF6 to obtain 5 moles of the compound?
2008-3-3 13:40:44 by Skinskin
Okay, I'm not sure if I did this right, but this is what I did.
5 mol of SF6 x (146.07 g SF6 / 1 mol SF6) = 730.2 g SF6
Then I subtracted what the total should be by what you have already:
730.2 - 486 = 244.2 g needed